Sustainable energy and the Kardashev scale

The y-axis is power; the x-axis is time. For a finite energy resource, the product [energy] is a constant, which is a diagonal line on this (log-log) plot. This represents, for a given civilization power consumption (y axis), the time scale over which it is maintainable (x axis). For renewable sources, the limiting factor is power - a flat horizontal line.

Energy potential by source

The units are in watts of thermal power equivalent. For some sources (e.g. wind), this does not make sense. So I've multiplied them by a factor of three. This is roughly an equal footing: for instance, 1/3rd is a typical thermal power plant efficiency. But vehicle engines are less efficient. And natural gas heat is more efficient (100%, actually). So the exact factor is debatable. Luckily this plot is logarithmic.

For the nuclear reactions, I use the following energy densities. For D+T fusion, 17.6 MeV over 4 amu = 424 TJ/kg. (Why 4 amu not 5? Because this is really D+D fusion, breeding tritium from its own neutron flux.) For proton-proton fusion, 26.73 MeV over 2 amu = 645 TJ/kg. For the fission breeding cycles, 190 MeV over 238 amu = 77 TJ/kg. For the once-through fuel cycle (the current method), we're limited to the fissile isotopes (U-235), and even then the limiting factor is not energy potential but the mechanical lifetime of fuel rods. Assuming enrichment from 0.7% to 3% U-235, and a burnup of 60 gigawatt days per metric ton U, this is 1.2 TJ/kg of the original, natural uranium.

For the fusion reactions, I use the mass of the earth's hydrosphere, 1.4 10^21 kg, as the supply of hydrogen fuel. 1/9th of the mass is hydrogen, and of that, 0.03% is deuterium. This excepts the "Jupiter" scenario, which is total fusion of the entire 1.9*10^27 kg mass of Jupiter (mostly pure H2).

There are three solar scenarios. One is the energy potential of the entire surface of the earth. Another is a Dyson ring, 10 kilometers in width at a solar radius of 10 million km. The last is a complete Dyson sphere, which is level II on the Kardashev scale for extraterrestial civilizations.

For the fission fuel supply, there are six lines, properly representing the wide range of figures represented in media sources, including the alarmist 'peak uranium' stories which use the lowest figure (overlaps natural gas). They are the permutations of three levels of ore - high-level conventional, phosphate rocks, and seawater - and closed vs. once-through fuel cycles (as above). From the IAEA red book, the first two numbers are estimated 4.7 million and 35 million metric tons uranium metal, respectively. The seawater figure is 4.5 billion tons, from the concentration figure of 3.2 ppb and the mass of the earths' oceans (given earlier). Note the seawater figure flattens horizontally at a certain level: this represents the rate of erosion of uranium from rivers, as referenced by Bernard Cohen in this Am. J. Phys. article. (32,000 tons/year). In this sense, fission is indeed a fully renewable resource, although at a far lower potential than wind or solar.

For wind, wave, geothermal, I simply stole figures from wikipedia [1] [2] [3]. The wind figure potential is slightly pragmatic, in that it ignores wind over open ocean (unlike the solar power figure). Same with the wave figure - apparently it only includes near-shore waves (but this makes small difference, since the "build-up" length for ocean waves is thousands of miles anyway: a mid-ocean wave farm would leave a wake thousands of miles long). The geothermal figure is the geological rate of heat dissipation out of the earth's crust, which is probably a huge overestimate. (But I'm ignoring near-surface pockets of heat, which can be exploited faster than natural conduction rates, but non-renewably so.)

I coudn't find a hydroelectric potential figure, so I made a quick estimate. From the histogram, I eyeballed an estimate of 500m for the average elevation of earth terrain (above sea level). Likewise, I eyeballed an average rainfall of 100 cm/year. Assuming they are uncorrelated, this represents a hydroelectric potential of 0.15 W/m^2, or an upper limit of 20 TW for the entire earth. This is the blue line between geothermal and ocean uranium breeders (they are all squished together).

Don't forget, I multiplied hydro, wind, and wave potentials by 3 to convert to thermal power equivalents. So the 20 TW of hydropower electricity are slightly greater than the 40 GW of geothermal heat.

The fossil fuel figures (coal/oil/gas) are from BP's statistical review. They are proven reserves, so they are underestimates.

Finally, the biomass figure is my own estimate, based on the IPCC figure for the carbon throughput of photosynthesis on earth (120 billion tons/year). This is the entire biosphere, not just anthropogenic farming.

The demand figures are (i) current world (thermal energy) consumption, and (ii) my guess at a near-future stablization point, which is a population of 10 billion with the same per-capita energy consumption as present-day USA.

Suggest improvements in the comments, and I may include them.

7 comments:

  1. good article: some info. Look at uranium and thorium in the crust and not just oceans. also look in asteroids etc...

    http://nextbigfuture.com/2009/02/revisiting-duration-of-nuclear-power.html

    If all of the 2 ppm fuel was able to be mined for higher energy return then the energy cost of mining then about 20 trillion tons is accessible. And then about quadruple that by including thorium. The earth's crust has 6 ppm of Thorium and 2 ppm of Uranium. Some deep burn reactor approaches such as fusion/fission hybrids do not require any enrichment. Any uranium is usable not just uranium 235.

    80 trillion tons times 950 gigawatt days/ton times 24 billion watt/hours per GWd.
    1750 billion trillion kilowatthours.

    If looking to fusion jupiter. Also, look at all uranium/thorium in the solar system including kuiper belt and oort comet cloud.

    http://en.wikipedia.org/wiki/433_Eros

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  2. Interesting that a Type I "planetary" civilization more or less requires resources from elsewhere in the Solar System. Apparently there is no such thing as a pure Type I civilization.

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  3. I would endorce Brian Wang on Uranium/Thorium availability. We are never going to run out, provided that we resort to breeding technology.

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  4. I apologize for not responding earlier, I am an irresponsible blogger. Yes, I agree uranium and thorium in deep-crust granite, and in asteroids, should belong on this graph - the timescale is millions of years, and the graph already includes as speculative ideas as even Dyson spheres. I will add them in as soon I get a chance (I have a lot of other fixes planned, it's a pretty lousy graph right now).

    Brian - if you have any data on the heavy-element composition of asteroids, it would be very helpful. Right now I'm empty-handed.

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  5. We don't know the composition of the asteroids or the objects in the Oort comet cloud or the Kuiper belt in great detail.

    There definitely is a lot of metal (iron, platinum)

    http://science.howstuffworks.com/asteroid-mining1.htm

    One NASA report estimates that the mineral wealth of the asteroids in the asteroid belt might exceed $100 billion for each of the six billion people on Earth. John S. Lewis, author of the space mining book Mining the Sky, has said that an asteroid with a diameter of one kilometer would have a mass of about two billion tons. There are perhaps one million asteroids of this size in the solar system. One of these asteroids, according to Lewis, would contain 30 million tons of nickel, 1.5 million tons of metal cobalt and 7,500 tons of platinum. The platinum alone would have a value of more than $150 billion.


    The outer Oort cloud is believed to contain several trillion individual comet nuclei larger than approximately 1.3 km (about 500 billion with absolute magnitudes brighter than 10.9), with neighboring comets typically tens of millions of kilometres apart. Its total mass is not known with certainty, but, assuming that Halley's comet is a suitable prototype for all comets within the outer Oort cloud, the estimated combined mass is 3 × 10^25 kilograms, or roughly five times the mass of the Earth.

    Models predict that the inner cloud should have tens or hundreds of times as many cometary nuclei as the outer halo; it is seen as a possible source of new comets to resupply the relatively tenuous outer cloud as the latter's numbers are gradually depleted

    http://en.wikipedia.org/wiki/Kuiper_belt

    the collective mass of the Kuiper belt is relatively low. The upper limit to the total mass is estimated at roughly a tenth the mass of the Earth, with some estimates placing it at a thirtieth an Earth mass.

    There is uranium and thorium on Mars
    http://adsabs.harvard.edu/abs/1981Geokh.......10B

    there is uranium on the moon
    http://www.space.com/scienceastronomy/090629-uranium-moon.html

    Several of the larger moons in the solar system and planets could have substantial percentages of uranium in their cores. But conflicting theories. Some spectral analysis of the surface of some solar bodies a couple of sampling missions and guesses at what is in the core of objects is what we are going on.
    http://www.absoluteastronomy.com/topics/Planetary_core

    Meteors tend to only have 0.008 ppm uranium
    http://www.world-nuclear.org/info/inf78.html


    http://www.physicsforums.com/archive/index.php/t-249773.html

    http://www.astro.psu.edu/users/kluhman/a5/lec11.html
    One theory is that there is more metals in the inner solar system. That would mean most of the uranium is Mars, Mercury, Earth Venus and asteroid belt.

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  6. I wrote up my research on how much uranium there is in the solar system. 600 trillion tons not in the sun. The Sun should have 500 times that. Those figures could be 40 times too low depending on what theory's are right.

    http://nextbigfuture.com/2009/08/how-much-uranium-is-in-solar-system.html

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  7. If for some reason a K1 or K2 civilization is not already going to other solar systems anyway, a lazy K1 or K2 civilization could wait for close passes and then raid other solar systems for colonization or resources.

    http://www.cnn.com/2004/TECH/space/10/26/rebel.stars/

    Our next known close encounter with another star will occur 1.4 million years from now.

    A star named Gliese 710, found by Hipparcos and reported in 1999, will pass within 1 light-year of the sun. That puts it some 70,000 times the distance from Earth to the sun, on the very fringes of our solar system where icy objects are thought to roam in what's known as the Oort Cloud.

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